WebOct 27, 2024 · Query the Western Longitude ( LONG_W )where the smallest Northern Latitude ( LAT_N) in STATION is greater than 38.7780 . Round your answer to 4 decimal places. Query a count of the number of ... WebINSTR: The instr(X,Y) function finds the first occurrence of string Y within string X and returns the number of prior characters plus 1, or 0 if Y is nowhere found within X.
Query the list of CITY names from STATION that do not start with …
Webyou can also remove the length function and use this: Select distinct (CITY) from STATION where lower (substr (CITY, 1, 1)) in ('a', 'e', 'i', 'o', 'u') and lower (substr (CITY, -1, 1)) in ('a', 'e', 'i', 'o', 'u'); 0 Parent Permalink tejshrithite 1 year ago correct. working 0 Parent Permalink the people profession now and for the future
十个Pandas的另类数据处理技巧-Python教程-PHP中文网
WebAn easy way to get around these issues of case-sensitivity is to use the UPPER () or LOWER () string functions to standardize capitalization on the values: SELECT * from contributors … WebJul 5, 2024 · Solution 1. As BackSlash have already commented, you've written the wrong REGEXP_LIKE pattern and you should change it to '^[aeiou].+', or you can even ommit .+ from your pattern, as you're only interested in the first letter of your string (containing more than 1 character): . select city from station where REGEXP_LIKE(city,'^[aeiou]'); Example with test … Webtry with MySQL solution :select distinct CITY from STATION where substr(CITY, -1, 1) in ('a','e','i','o','u');Here "distinct" will solve the problem of duplicate value and "substring" … the people principle